Function tryFn

Wrap fn so calling it returns defaultValue instead of throwing.

Example

const parse = tryFn(JSON.parse, {});

parse('invalid'); // {}
parse('{"a":1}'); // { a: 1 }

tryFn<Fn extends AnyFunction>(
fn: Fn,
): (...args: Parameters<Fn>) => ReturnType<Fn> | undefined
Type Parameters
- Fn extends AnyFunction
Parameters
- fn: Fn
Returns (...args: Parameters<Fn>) => ReturnType<Fn> | undefined
- Defined in src/tryFn.ts:3
tryFn<Fn extends AnyFunction, DefaultValue>(
fn: Fn,
defaultValue: DefaultValue,
): (...args: Parameters<Fn>) => DefaultValue | ReturnType<Fn>
Type Parameters
- Fn extends AnyFunction
- DefaultValue
Parameters
- fn: Fn
- defaultValue: DefaultValue
Returns (...args: Parameters<Fn>) => DefaultValue | ReturnType<Fn>
- Defined in src/tryFn.ts:5